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401
sales
bird
Give the product's name brought by Aaron Alexander.
train
hard
SELECT DISTINCT t1.name FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid INNER JOIN customers AS t3 ON t2.customerid = t3.customerid WHERE t3.firstname = 'aaron' AND t3.lastname = 'alexander'
402
sales
bird
Give the product ID and name of the product with the highest prices among the quantity ranges from 400 to 500.
train
hard
SELECT t1.productid, t1.name FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t2.quantity BETWEEN 400 AND 500 ORDER BY t1.price DESC LIMIT 1
403
sales
bird
Among customers named Kate, who has the highest quantity?
train
hard
SELECT t2.firstname, t2.lastname FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid WHERE t2.firstname = 'kate' ORDER BY t1.quantity DESC LIMIT 1
404
sales
bird
Among the products that have price ranges from 100 to 150, what is the customer ID and sales ID of the product with a quantity lower than 25?
train
hard
SELECT t2.customerid, t2.salesid FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t1.price BETWEEN 100 AND 150 AND t2.quantity < 25
405
sales
bird
List the quantity and price of the product bought by Abigail Henderson.
train
hard
SELECT t2.quantity, t1.price FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid INNER JOIN customers AS t3 ON t2.customerid = t3.customerid WHERE t3.firstname = 'abigail' AND t3.lastname = 'henderson'
406
sales
bird
In sales with a quantity of 60, how many of them have a price not greater than 500?
train
hard
SELECT COUNT(t1.productid) FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t2.quantity = 60 AND t1.price <= 500
407
sales
bird
In customers with the first name of Erica, how many of them bought a quantity below 200?
train
hard
SELECT COUNT(t1.productid) FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid WHERE t2.firstname = 'erica' AND t1.quantity < 200
408
sales
bird
Among products bought by Kathryn Ashe, what is the name of the product with the highest quantity?
train
hard
SELECT t1.name FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid INNER JOIN customers AS t3 ON t2.customerid = t3.customerid WHERE t3.firstname = 'kathryn' AND t3.lastname = 'ashe' ORDER BY t2.quantity DESC LIMIT 1
409
sales
bird
What is the price and quantity of the product named Seat Tube?
train
hard
SELECT DISTINCT t2.price, t1.quantity FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid WHERE t2.name = 'seat tube'
410
sales
bird
What is the price and name of the product bought by Erica Xu?
train
hard
SELECT t3.price, t3.name FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid INNER JOIN products AS t3 ON t1.productid = t3.productid WHERE t2.firstname = 'erica' AND t2.lastname = 'xu'
411
sales
bird
List the sales ID of the product with a quantity of 590 and named "External Lock Washer 7".
train
hard
SELECT t1.salesid FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid WHERE t2.name = 'external lock washer 7' AND t1.quantity = 590
412
sales
bird
In sales ID between 30 and 40, who is the customer that bought a total quantity of 403?
train
hard
SELECT t2.firstname, t2.lastname FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid WHERE t1.quantity = 403 AND t1.salesid BETWEEN 30 AND 40
413
sales
bird
List the customer's ID and last name of the customer that purchased a product with a quantity greater than 90% of the average quantity of all listed products.
train
hard
SELECT t2.customerid, t2.lastname FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid WHERE t1.quantity > (SELECT AVG(quantity) FROM sales) * 0.9
414
sales
bird
Among the sales ID ranges from 1 to 200, what is the percentage of the products with a price ranging from 200 to 300?
train
hard
SELECT CAST(CAST(SUM(IIF(t2.price BETWEEN 200 AND 300, 1, 0)) AS REAL) * 100 AS REAL) / COUNT(t2.price) FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid WHERE t1.salesid BETWEEN 1 AND 200
415
sales
bird
What is the name of the most expensive product?
train
easy
SELECT name FROM products WHERE price = (SELECT MAX(price) FROM products)
416
sales
bird
How many customers are named Madison?
train
easy
SELECT COUNT(customerid) FROM customers WHERE firstname = 'madison'
417
sales
bird
How many types of "HL Touring Frames" are there?
train
easy
SELECT COUNT(productid) FROM products WHERE name LIKE '%hl touring frame%'
418
sales
bird
How many customers share the most common last name?
train
hard
SELECT COUNT(customerid) FROM customers GROUP BY lastname ORDER BY COUNT(lastname) DESC LIMIT 1
419
sales
bird
How many free or gift products are there?
train
easy
SELECT COUNT(productid) FROM products WHERE price = 0
420
sales
bird
What is the name of the sales person who handled the highest number of sales?
train
hard
SELECT t1.firstname, t1.middleinitial, t1.lastname FROM employees AS t1 INNER JOIN sales AS t2 ON t2.salespersonid = t1.employeeid GROUP BY t2.salespersonid, t1.firstname, t1.middleinitial, t1.lastname ORDER BY COUNT(t2.salesid) DESC LIMIT 1
421
sales
bird
What is the full name of the customer who purchased the highest amount of total price in a single purchase?
train
hard
SELECT t2.firstname, t2.middleinitial, t2.lastname FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid INNER JOIN products AS t3 ON t1.productid = t3.productid GROUP BY t1.salesid, t1.quantity, t3.price, firstname, middleinitial, lastname ORDER BY t1.quantity * t3.price DESC LIMIT 1
422
sales
bird
How many "Mountain-500 Black 42" were sold in total?
train
hard
SELECT SUM(t2.quantity) FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t1.name = 'mountain-500 black, 42'
423
sales
bird
How much is the total amount of sales handled by Heather McBadden?
train
hard
SELECT SUM(t2.quantity * t3.price) FROM employees AS t1 INNER JOIN sales AS t2 ON t1.employeeid = t2.salespersonid INNER JOIN products AS t3 ON t2.productid = t3.productid WHERE t1.firstname = 'heather' AND t1.lastname = 'mcbadden'
424
sales
bird
How many "Mountain-100 Silver, 38" were sold by Stearns MacFeather?
train
hard
SELECT SUM(t2.quantity) FROM employees AS t1 INNER JOIN sales AS t2 ON t1.employeeid = t2.salespersonid INNER JOIN products AS t3 ON t2.productid = t3.productid WHERE t1.firstname = 'stearns' AND t1.lastname = 'macfeather' AND t3.name = 'mountain-100 silver, 38'
425
sales
bird
How many type of products did Dalton M. Coleman purchase?
train
hard
SELECT COUNT(t2.productid) FROM customers AS t1 INNER JOIN sales AS t2 ON t1.customerid = t2.customerid WHERE t1.firstname = 'dalton' AND t1.middleinitial = 'm' AND t1.lastname = 'coleman'
426
sales
bird
What are the full names of the top 3 employees who handled the highest number of sales?
train
hard
SELECT t1.firstname, t1.middleinitial, t1.lastname FROM employees AS t1 INNER JOIN sales AS t2 ON t1.employeeid = t2.salespersonid GROUP BY t2.salespersonid, t1.firstname, t1.middleinitial, t1.lastname ORDER BY COUNT(t2.salesid) DESC LIMIT 3
427
sales
bird
Among the "Mountain-500 Black" product types, which type was purchased the most?
train
hard
SELECT t1.name FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t1.name LIKE 'mountain-500 black%' GROUP BY t2.quantity, t1.name ORDER BY SUM(t2.quantity) DESC LIMIT 1
428
sales
bird
How many employees sold "ML Road Frame-W - Yellow, 40"?
train
hard
SELECT COUNT(t2.salespersonid) FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid WHERE t1.name = 'ml road frame-w - yellow, 40'
429
sales
bird
How many chainring bolts were sold under sales ID 551971?
train
hard
SELECT t1.quantity FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid WHERE t2.name = 'chainring bolts' AND t1.salesid = 551971
430
sales
bird
How many employees sold over 20,000 quantities of "Touring-2000 Blue, 50"?
train
easy
SELECT COUNT(*) FROM (SELECT SUM(quantity) FROM sales WHERE productid IN (SELECT productid FROM products WHERE name = 'touring-2000 blue, 50') GROUP BY quantity, salespersonid HAVING SUM(quantity) > 20000)
431
sales
bird
What is the total cost of all the "Road-650, Red, 60" products that Abraham E. Bennet sold?
train
hard
SELECT SUM(t2.quantity * t3.price) FROM employees AS t1 INNER JOIN sales AS t2 ON t1.employeeid = t2.salespersonid INNER JOIN products AS t3 ON t2.productid = t3.productid WHERE t1.firstname = 'abraham' AND t1.middleinitial = 'e' AND t1.lastname = 'bennet' AND t3.name = 'road-650 red, 60'
432
sales
bird
Which product has the highest total amount of quantity sold? Calculate its overall total price.
train
hard
SELECT t1.name, SUM(t2.quantity * t1.price) FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid GROUP BY t1.productid, t1.name ORDER BY SUM(t2.quantity) DESC LIMIT 1
433
sales
bird
List the first name of all the customers whose last name is Chen.
train
easy
SELECT firstname, lastname FROM customers WHERE lastname = 'chen'
434
sales
bird
Among the employee names, what is the most common middle initial?
train
hard
SELECT middleinitial FROM employees GROUP BY middleinitial ORDER BY COUNT(middleinitial) DESC LIMIT 1
435
sales
bird
What is the average price of products that cost between 100 and 200?
train
medium
SELECT AVG(price) FROM products WHERE price BETWEEN 100 AND 200
436
sales
bird
Find and list the full name of customers who bought products above-average quantity.
train
hard
SELECT t2.firstname, t2.middleinitial, t2.lastname FROM sales AS t1 INNER JOIN customers AS t2 ON t1.customerid = t2.customerid GROUP BY t1.quantity HAVING t1.quantity > (SELECT AVG(quantity) FROM sales)
437
sales
bird
Give the full name of the customer who bought the most amount of products.
train
hard
SELECT t3.firstname, t3.middleinitial, t3.lastname FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid INNER JOIN customers AS t3 ON t2.customerid = t3.customerid ORDER BY t2.quantity * t1.price DESC LIMIT 1
438
sales
bird
Of the employees who sold Blade, who has the most amount of sales?
train
hard
SELECT t1.firstname, t1.middleinitial, t1.lastname FROM employees AS t1 INNER JOIN sales AS t2 ON t1.employeeid = t2.salespersonid INNER JOIN products AS t3 ON t2.productid = t3.productid ORDER BY t2.quantity * t3.price DESC LIMIT 1
439
sales
bird
List the full name of customers who spend more than 50,000 in descending order the amount spend.
train
hard
SELECT DISTINCT t3.firstname, t3.middleinitial, t3.lastname FROM products AS t1 INNER JOIN sales AS t2 ON t1.productid = t2.productid INNER JOIN customers AS t3 ON t2.customerid = t3.customerid WHERE t2.quantity * t1.price > 50000
440
sales
bird
Name the product that sold the most quantity.
train
hard
SELECT t2.name FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid ORDER BY t1.quantity DESC LIMIT 1
441
sales
bird
Find and list the products that sold below the average quantity.
train
hard
SELECT DISTINCT t2.name FROM sales AS t1 INNER JOIN products AS t2 ON t1.productid = t2.productid WHERE t1.quantity < (SELECT AVG(quantity) FROM sales)
442
retail_world
bird
Please list the names of all the products whose supplier is in Japan.
train
hard
SELECT t1.productname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t2.country = 'japan'
443
retail_world
bird
Give the full name of the youngest employee.
train
easy
SELECT firstname, lastname FROM employees WHERE birthdate = (SELECT MAX(birthdate) FROM employees)
444
retail_world
bird
Who is the newest hired employee? Give the full name.
train
easy
SELECT firstname, lastname FROM employees WHERE hiredate = (SELECT MAX(hiredate) FROM employees)
445
retail_world
bird
Provide the number of orders that were handled by Michael Suyama.
train
hard
SELECT COUNT(t2.orderid) FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t1.firstname = 'michael' AND t1.lastname = 'suyama'
446
retail_world
bird
How many kinds of products are there in the the category of "dairy products"?
train
hard
SELECT COUNT(t1.productid) FROM products AS t1 INNER JOIN categories AS t2 ON t1.categoryid = t2.categoryid WHERE t2.categoryname = 'dairy products'
447
retail_world
bird
Which category does "tofu" belong to?
train
hard
SELECT t2.categoryname FROM products AS t1 INNER JOIN categories AS t2 ON t1.categoryid = t2.categoryid WHERE t1.productname = 'tofu'
448
retail_world
bird
Give the contact name of the supplier for the product "Gudbrandsdalsost".
train
hard
SELECT t2.contactname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t1.productname = 'gudbrandsdalsost'
449
retail_world
bird
Tell the country name of the supplier for "Scottish Longbreads".
train
hard
SELECT t2.country FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t1.productname = 'scottish longbreads'
450
retail_world
bird
How many customers are there in the country with the highest number of customers?
train
hard
SELECT COUNT(customerid) FROM customers GROUP BY country ORDER BY COUNT(customerid) DESC LIMIT 1
451
retail_world
bird
How many suppliers are there in the United States of America?
train
easy
SELECT COUNT(supplierid) FROM suppliers WHERE country = 'usa'
452
retail_world
bird
What is the name of the supplier that supplies the most products to the company?
train
hard
SELECT t1.supplierid FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid GROUP BY t1.supplierid ORDER BY COUNT(*) DESC LIMIT 1
453
retail_world
bird
What is the full name of the employee who handled the highest amount of orders?
train
hard
SELECT t1.firstname, t1.lastname FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid GROUP BY t1.firstname, t1.lastname ORDER BY COUNT(*) DESC LIMIT 1
454
retail_world
bird
What is the name of the contact person of the Pavlova supplier company?
train
hard
SELECT t2.contactname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t1.productname = 'pavlova'
455
retail_world
bird
What is the family name of the employee who shipped the order 10521 to CACTU?
train
hard
SELECT t1.lastname FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t2.orderid = 10521 AND t2.customerid = 'cactu'
456
retail_world
bird
What are the products that belong to the beverage category?
train
hard
SELECT t2.productname FROM categories AS t1 INNER JOIN products AS t2 ON t1.categoryid = t2.categoryid WHERE t1.categoryname = 'beverages'
457
retail_world
bird
What is the description of the category that tofu belongs to?
train
hard
SELECT t1.description FROM categories AS t1 INNER JOIN products AS t2 ON t1.categoryid = t2.categoryid WHERE t2.productname = 'tofu'
458
retail_world
bird
Who is the person to contact to get Camembert Pierrot?
train
hard
SELECT t2.contactname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t1.productname = 'camembert pierrot'
459
retail_world
bird
How many territories are there?
train
easy
SELECT COUNT(territoryid) FROM territories
460
retail_world
bird
List down the customer ids who placed order with Michael Suyama.
train
hard
SELECT t2.customerid FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t1.firstname = 'michael' AND t1.lastname = 'suyama'
461
retail_world
bird
How many orders have Margaret Peacock placed?
train
hard
SELECT COUNT(t2.employeeid) FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t1.firstname = 'margaret' AND t1.lastname = 'peacock'
462
retail_world
bird
Calculate the total products that are supplied by Japan suppliers.
train
hard
SELECT COUNT(t1.supplierid) FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t2.country = 'japan'
463
retail_world
bird
What is the contact name for product Teatime Chocolate Biscuits?
train
hard
SELECT t2.contactname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t1.productname = 'teatime chocolate biscuits'
464
retail_world
bird
How many customers are there in Berlin, Germany?
train
medium
SELECT COUNT(city) FROM customers WHERE country = 'germany' AND city = 'berlin'
465
retail_world
bird
What percentage of orders were placed by customers in Madrid city in 1996?
train
hard
SELECT CAST(CAST(COUNT(CASE WHEN t1.city = 'madrid' THEN 1 ELSE NULL END) AS REAL) * 100 AS REAL) / COUNT(t1.city) FROM customers AS t1 INNER JOIN orders AS t2 ON t1.customerid = t2.customerid WHERE STRFTIME('%y', t2.orderdate) = 1996
466
retail_world
bird
In 1996, how many orders were from customers in the UK?
train
hard
SELECT COUNT(t1.customerid) FROM customers AS t1 INNER JOIN orders AS t2 ON t1.customerid = t2.customerid WHERE STRFTIME('%y', t2.orderdate) = '1996' AND t1.country = 'uk'
467
retail_world
bird
Please calculate the number of orders from customers by country in 1996.
train
hard
SELECT COUNT(t2.customerid) FROM customers AS t1 INNER JOIN orders AS t2 ON t1.customerid = t2.customerid WHERE STRFTIME('%y', t2.orderdate) = '1996' GROUP BY t1.country
468
retail_world
bird
Which country are the majority of the suppliers located?
train
hard
SELECT country FROM suppliers GROUP BY country ORDER BY COUNT(supplierid) DESC LIMIT 1
469
retail_world
bird
In August of 1996, how many orders were placed by the customer with the highest amount of orders?
train
medium
SELECT COUNT(orderid) FROM orders WHERE orderdate LIKE '1996-08%' GROUP BY customerid ORDER BY COUNT(orderid) DESC LIMIT 1
470
retail_world
bird
What are the ID and description of the condiments category?
train
medium
SELECT categoryid, description FROM categories WHERE categoryname = 'condiments'
471
retail_world
bird
What were the products supplied by the company in Spain?
train
hard
SELECT t1.productname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t2.country = 'spain'
472
retail_world
bird
How many orders were made by the customers in Ireland.
train
hard
SELECT COUNT(t2.orderid) FROM customers AS t1 INNER JOIN orders AS t2 ON t1.customerid = t2.customerid WHERE t1.country = 'ireland'
473
retail_world
bird
Provide the full name of the employee who processed the sales order with ID 10274.
train
hard
SELECT t1.firstname, t1.lastname FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t2.orderid = 10274
474
retail_world
bird
How many suppliers does Northwind have in USA?
train
easy
SELECT COUNT(supplierid) FROM suppliers WHERE country = 'usa'
475
retail_world
bird
How many companies do ship Northwind's orders?
train
easy
SELECT COUNT(shipperid) FROM shippers
476
retail_world
bird
Indicate category name of soft drinks, coffees, teas, beers, and ales in description list.
train
medium
SELECT categoryname FROM categories WHERE description = 'soft drinks, coffees, teas, beers, and ales'
477
retail_world
bird
List all product names under Confections.
train
hard
SELECT t1.productname FROM products AS t1 INNER JOIN categories AS t2 ON t1.categoryid = t2.categoryid WHERE t2.categoryname = 'confections'
478
retail_world
bird
Name the products where the suppliers come from Finland.
train
hard
SELECT t1.productname FROM products AS t1 INNER JOIN suppliers AS t2 ON t1.supplierid = t2.supplierid WHERE t2.country = 'finland'
479
retail_world
bird
The product 'Mozzarella di Giovanni' belongs in which category? Include the category's description as well.
train
hard
SELECT t2.categoryname, t2.description FROM products AS t1 INNER JOIN categories AS t2 ON t1.categoryid = t2.categoryid WHERE t1.productname = 'mozzarella di giovanni'
480
retail_world
bird
How many suppliers are from UK?
train
easy
SELECT COUNT(supplierid) FROM suppliers WHERE country = 'uk'
481
retail_world
bird
What is the name of product with the ID of 77?
train
easy
SELECT productname FROM products WHERE productid = 77
482
retail_world
bird
How many orders were handled by Michael Suyama. State the order ID.
train
hard
SELECT COUNT(t2.orderid) FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t1.firstname = 'michael' AND t1.lastname = 'suyama'
483
retail_world
bird
How many customers are located in London?
train
easy
SELECT COUNT(customerid) FROM customers WHERE city = 'london'
484
retail_world
bird
List out the full name of employee who has birth day on "3/4/1955 12:00:00 AM".
train
easy
SELECT firstname, lastname FROM employees WHERE birthdate = '1955-03-04 00:00:00'
485
retail_world
bird
Mention the first name of employee who took care the order id 10250.
train
hard
SELECT t1.firstname, t1.lastname FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t2.orderid = 10250
486
retail_world
bird
When was the employee who handled order id 10281 hired?
train
hard
SELECT t1.hiredate FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t2.orderid = 10281
487
retail_world
bird
Give the full name of employee who handled the order id 10280.
train
hard
SELECT t1.firstname, t1.lastname FROM employees AS t1 INNER JOIN orders AS t2 ON t1.employeeid = t2.employeeid WHERE t2.orderid = 10280
488
retails
bird
How many kinds of items are returned in order no.5?
train
medium
SELECT COUNT(l_linenumber) FROM lineitem WHERE l_orderkey = 5 AND l_returnflag = 'r'
489
retails
bird
When was the latest date the items of order no.1 were shipped?
train
medium
SELECT MAX(l_shipdate) FROM lineitem WHERE l_orderkey = 1
490
retails
bird
Which order has a higher priority, order no. 4 or order no. 36?
train
medium
SELECT l_orderkey FROM lineitem WHERE l_orderkey IN (4, 36) ORDER BY l_shipdate DESC LIMIT 1
491
retails
bird
What is the comment of the order with the highest total price?
train
medium
SELECT o_comment FROM orders WHERE o_totalprice = (SELECT MAX(o_totalprice) FROM orders)
492
retails
bird
What is the phone number of Customer#000000001?
train
easy
SELECT c_phone FROM customer WHERE c_name = 'customer#000000001'
493
retails
bird
How many orders in total have the customers in the household segment made?
train
hard
SELECT COUNT(t1.o_orderkey) FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey WHERE t2.c_mktsegment = 'household'
494
retails
bird
Among all the orders made by a customer in the household segment, what is the highest total price?
train
hard
SELECT MAX(t1.o_totalprice) FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey WHERE t2.c_mktsegment = 'household'
495
retails
bird
Please list the order comments of all the orders made by customers in the household segment.
train
hard
SELECT t1.o_comment FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey WHERE t2.c_mktsegment = 'household'
496
retails
bird
Please give the name of the customer who has made the single order with the highest total price.
train
hard
SELECT t2.c_name FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey ORDER BY t1.o_totalprice DESC LIMIT 1
497
retails
bird
Please list the order keys of all the orders made by a customer whose account is in debt.
train
hard
SELECT t1.o_orderkey FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey WHERE t2.c_acctbal < 0
498
retails
bird
Among the orders made by customers in the household segment, how many of them are urgent?
train
hard
SELECT COUNT(t1.o_orderpriority) FROM orders AS t1 INNER JOIN customer AS t2 ON t1.o_custkey = t2.c_custkey WHERE t2.c_mktsegment = 'household' AND t1.o_orderpriority = '1-urgent'
499
retails
bird
How many customers are in Brazil?
train
hard
SELECT COUNT(t1.c_custkey) FROM customer AS t1 INNER JOIN nation AS t2 ON t1.c_nationkey = t2.n_nationkey WHERE t2.n_name = 'brazil'
500
retails
bird
Please list the phone numbers of all the customers in the household segment and are in Brazil.
train
hard
SELECT t1.c_phone FROM customer AS t1 INNER JOIN nation AS t2 ON t1.c_nationkey = t2.n_nationkey WHERE t1.c_mktsegment = 'household' AND t2.n_name = 'brazil'